Question:
When the switch S, in the circuit shown, is closed then the valued of current $i$ will be:
Correct Option: , 2
Solution:
Let voltage at $\mathrm{C}=\mathrm{xV}$
From kirchhoff's current law,
$\mathrm{KCL}: \mathrm{i}_{1}+\mathrm{i}_{2}=\mathrm{i}$
$\frac{20-x}{2}+\frac{10-x}{4}=\frac{x-0}{2} \Rightarrow x=10$
$\therefore \mathrm{i}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{\mathrm{X}}{\mathrm{R}}=\frac{10}{2}=5 \mathrm{~A}$
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