When two soap bubbles


When two soap bubbles of radii a and $b$ ( $b>$ a) coalesce, the radius of curvature of common surface is :

  1. $\frac{a b}{b-a}$

  2. $\frac{a+b}{a b}$

  3. $\frac{b-a}{a b}$

  4. $\frac{a b}{a+b}$

Correct Option: 1


Excess pressure at common surface is given by

$\mathrm{P}_{\mathrm{ex}}=4 \mathrm{~T}\left(\frac{1}{\mathrm{a}}-\frac{1}{\mathrm{~b}}\right)=\frac{4 \mathrm{~T}}{\mathrm{r}}$

$\therefore \frac{1}{\mathrm{r}}=\frac{1}{\mathrm{a}}-\frac{1}{\mathrm{~b}}$


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