Question:
Write the sum of real roots of the equation $x^{2}+|x|-6=0$.
Solution:
The given quadric equation is $x^{2}+|x|-6=0$
Here, $a=1, b=\pm 1$ and, $c=-6$
As we know that $D=b^{2}-4 a c$
Putting the value of $a=1, b=\pm 1$ and, $c=-6$
$=(\pm 1)^{2}-4 \times 1 \times-6$
$=1+24$
$=25$
Since, $D \geq 0$
Therefore, root of the given equation are real and distinct.
Thus, sum of the roots be $=0$
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