Question:
Write the zeros of the quadratic polynomial $f(x)=6 x^{2}-3$
Solution:
To find the zeros of the quadratic polynomial we will equate f(x) to 0
$\therefore f(x)=0$
$\Rightarrow 6 x^{2}-3=0$
$\Rightarrow 3\left(2 x^{2}-1\right)=0$
$\Rightarrow 2 x^{2}-1=0$
$\Rightarrow 2 x^{2}=1$
$\Rightarrow x^{2}=\frac{1}{2}$
$\Rightarrow x=\pm \frac{1}{\sqrt{2}}$
Hence, the zeros of the quadratic polynomial $f(x)=6 x^{2}-3$ are $\frac{1}{\sqrt{2}},-\frac{1}{\sqrt{2}}$.