Radioactivity – JEE Advanced Previous Year Questions with Solutions

JEE Advanced Previous Year Questions of Physics with Solutions are available at eSaral. Practicing JEE Advanced Previous Year Papers Questions of Physics will help the JEE aspirants in realizing the question pattern as well as help in analyzing weak & strong areas.

Get detailed Class 11th & 12th Physics Notes to prepare for Boards as well as competitive exams like IIT JEE, NEET etc.

eSaral helps the students in clearing and understanding each topic in a better way. eSaral is providing complete chapter-wise notes of Class 11th and 12th both for all subjects.



Click Here for JEE main Previous Year Topic Wise Questions of Physics with Solutions 


Download eSaral app  for free study material and video tutorials.



Previous Years JEE Advanced Questions

Paragraph for Questions 3 and 4

The -decay process, discovered around 1900, is basically the decay of a neutron (n). In the laboratory, a proton (p) and an electron $\left(\mathrm{e}^{-}\right)$ are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a two-body decay process, it was predicted theoretically that the kinetic energy of the electron should be a constant. But experimentally, it was observed that the electron kinetic energy has a continuous spectrum. Considering a three-body decay process, $\mathrm{n} \rightarrow \mathrm{p}+\mathrm{e}^{-}+\vec{v}_{e}$ , around 1930, Pauli explained the observed electron energy spectrum. Assuming the anti-neutrino $\left(\vec{v}_{e}\right)$ to be massless and possessing negligible energy, and the neutron to be at rest, momentum and energy conservation principles are applied. From this calculation, the maximum kinetic energy of the electron is $0.8 \times 10^{6} \mathrm{eV}$ . The kinetic energy carried by the proton is only the recoil energy.


Leave a comment

Please enter comment.
Please enter your name.