Application of diode as a rectifier:
An electronic device that converts alternating current into Direct current is called a rectifier.Half wave rectifier:
A rectifier, which rectifies only one half of each ac supply cycle is called a half-wave rectifier.
During the first half of the input cycle, the junction diode gets forward bias. The conventional current will flow. The upper end of $R_{L}$ will be positive potential with respect to the lower end during the second half cycle junction diode will get reverse biased and hence no output will be obtained across $R_{L}$.
Input voltage
$\mathrm{V}_{\mathrm{i}}=\mathrm{V}_{\mathrm{m}} \sin \omega \mathrm{t}$
$\mathrm{i}=\mathrm{I}_{\mathrm{m}} \sin \omega \mathrm{t}$
for $0 \leq \omega t \leq \pi$
$\mathrm{i}=0$
for $\pi<\omega t<2 \pi$
$I_{m}=\frac{V_{m}}{R_{f}+R_{L}}$
here $\mathrm{R}_{\mathrm{f}}=$ forward resistance of diode
$R_{L}$ = load resistance
a. dc output current :
$\mathrm{I}_{\mathrm{dc}}=\frac{1}{2 \pi} \int_{0}^{2 \pi} \mathrm{idt}$
$=\frac{1}{2 \pi}\left[\int_{0}^{\pi} \mathrm{I}_{\mathrm{m}} \sin t \mathrm{dt}+\int_{\pi}^{2 \pi} 0 \mathrm{dt}\right]$
$\mathrm{I}_{\mathrm{dc}}=\frac{\mathrm{I}_{\mathrm{m}}}{\pi}=0.318 \mathrm{I}_{\mathrm{m}}$
b. dc output voltage:
$V_{d c}=I_{d c} \times R_{L}$
$=\frac{I_{m}}{\pi} \times R_{L}$
$=\frac{\mathrm{V}_{\mathrm{m}}}{\pi\left[1+\left(\mathrm{R}_{\mathrm{f}} / \mathrm{R}_{\mathrm{L}}\right)\right]}$
$V_{d c}=\frac{V_{m}}{\pi}=0.318 \mathrm{~V}_{\mathrm{m}}$
c. (Root mean square) RMS current:
$I_{r m s}=\left[\frac{1}{2 \pi} \int_{0}^{2 \pi} i^{2} d(t)\right]^{1 / 2}$
$=\frac{I_{m}}{2}$
same
$V_{r m s}=\frac{V_{m}}{2}$
So, that’s all from this blog. I hope you enjoyed this explanation of the half-wave rectifier and half-wave rectifier circuit diagram. If you liked this article then please share it with your friends.
Also Read
What is Diode in electronics
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