Here we have listed Class 9 maths chapter 1 exercise 1.5 solutions in PDF that is prepared by Kota’s top IITian’s Faculties by keeping Simplicity in mind.

If you want to score high in your class 9 Maths Exam then it is very important for you to have a good knowledge of all the important topics, so to learn and practice those topics you can use eSaral NCERT Solutions.

In this article, we have listed NCERT Solutions for Class 9 Maths chapter 1 Exercise 1.5 that you can download to start your preparations anytime.

So, without wasting more time Let’s start.

**Download The PDF of NCERT Solutions for Class 9 Maths chapter 1 Exercise 1.5 "Number System"**

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#### All Questions of Chapter 1 Exercise 1.5

Once you complete the chapter 1 then you can revise Ex. 1.5 by solving following questions

Q1. Classify the following numbers as rational or irrational:

(i) $2-\sqrt{5}$

(ii) $(3+\sqrt{23})-\sqrt{23}$

(iii) $\frac{2 \sqrt{7}}{7 \sqrt{7}}$

(iv) $\frac{1}{\sqrt{2}}$

(v) $2 \pi$

Q2. Simplify each of the following expressions:

(i) $(3+\sqrt{3})(2+\sqrt{2})$

(ii) $(3+\sqrt{3})(3-\sqrt{3})$

(iii) $(\sqrt{5}+\sqrt{2})^{2}$

(iv) $(\sqrt{5}-\sqrt{2})(\sqrt{5}+\sqrt{2})$

Q3. Recall, $\pi$ is defined as the ratio of the circumference (say $\mathrm{c}$ ) of a circle to its diameter (say d). That is, $\pi=\mathrm{c} / \mathrm{d}$. This seems to contradict the fact that $\pi$ is irrational. How will you resolve this contradiction?

Q4. Represent $\sqrt{9.3}$ on the number line.

Q5. Rationalise the denominators of the following :

(i) $\frac{1}{\sqrt{7}}$

(ii) $\frac{1}{\sqrt{7}-\sqrt{6}}$

(iii) $\frac{1}{\sqrt{5}+\sqrt{2}}$

(iv) $\frac{1}{\sqrt{7}-2}$

Also Read,

Class 9 Maths Revision Quick Videos.

Download Class 9 NCERT Maths Book

Download Class 9 NCERT Maths Exemplar

Download Complete Solutions for Class 9 chapter 1 Free PDF

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