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Here we have listed Class 9 maths chapter 2 exercise 2.2 solutions in PDF that is prepared by Kota’s top IITian’s Faculties by keeping Simplicity in mind.

If you want to score high in your class 9 Maths Exam then it is very important for you to have a good knowledge of all the important topics, so to learn and practice those topics you can use eSaral NCERT Solutions.

In this article, we have listed NCERT Solutions for Class 9 Maths chapter 2 Exercise 2.2 that you can download to start your preparations anytime.

So, without wasting more time Let’s start.

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Q1. Find the value of the polynomial $5 x-4 x^{2}+3$ at

(i) $\mathrm{x}=0$

(vi) $\mathrm{x}=-1$

(iii) $\mathrm{x}=2$

Q2. Find $\mathrm{p}(0), \mathrm{p}(1), \mathrm{p}(2)$, for each of the following polynomials :

(i) $p(y)=y^{2}-y+1$

(ii) $\mathrm{p}(\mathrm{t})=2+\mathrm{t}+2 \mathrm{t}^{2}-\mathrm{t}^{3}$

(iii) $\mathrm{p}(\mathrm{x})=\mathrm{x}^{3}$

(iv) $\mathrm{p}(\mathrm{x})=(\mathrm{x}-1)(\mathrm{x}+1)$

Q3. Verify whether the following are zeroes of the polynomial, indicated against them,

(i) $\mathrm{p}(\mathrm{x})=3 \mathrm{x}+1, \mathrm{x}=-\frac{1}{3}$

(ii) $\mathrm{p}(\mathrm{x})=5 \mathrm{x}-\pi, \mathrm{x}=\frac{4}{5}$

(iii) $\mathrm{p}(\mathrm{x})=\mathrm{x}^{2}-1, \mathrm{x}=1,-1$

(iv) $\mathrm{p}(\mathrm{x})=(\mathrm{x}+1)(\mathrm{x}-2), \mathrm{x}=-1,2$

(v) $\mathrm{p}(\mathrm{x})=\mathrm{x}^{2}, \mathrm{x}=0$

(vi) $\mathrm{p}(\mathrm{x})=\ell \mathrm{x}+\mathrm{m}, \mathrm{x}=-\frac{\mathrm{m}}{\ell}$

(vii) $\mathrm{p}(\mathrm{x})=3 \mathrm{x}^{2}-1, \mathrm{x}=-\frac{1}{\sqrt{3}}, \frac{2}{\sqrt{3}}$

(viii) $\mathrm{p}(\mathrm{x})=2 \mathrm{x}+1, \mathrm{x}=\frac{1}{2}$

Q4. Find the zero of the polynomial in each of the following cases:

(i) $p(x)=x+5$

(ii) $\mathrm{p}(\mathrm{x})=\mathrm{x}-5$

(iii) $\mathrm{p}(\mathrm{x})=2 \mathrm{x}+5$

(iv) $\mathrm{p}(\mathrm{x})=3 \mathrm{x}-2$

(v) $\mathrm{p}(\mathrm{x})=3 \mathrm{x}$

(vi) $\mathrm{p}(\mathrm{x})=\mathrm{ax}, \mathrm{a} \neq 0$

(vii) $\mathrm{p}(\mathrm{x})=\mathrm{cx}+\mathrm{d}, \mathrm{c} \neq 0, \mathrm{c}, \mathrm{d}$ are real numbers.

Also Read,

Download Class 9 NCERT Maths Book Free

Download Class 9 NCERT Maths Exemplar Free

Download Complete Solutions for Class 9 chapter 2 PDF

Class 9 Maths Chapter 1 Exercise 1.1 Solutions

Class 9 Maths Chapter 1 Exercise 1.2 Solutions

Class 9 Maths Chapter 1 Exercise 1.3 Solutions

If you have any Confusion related to NCERT Solutions for Class 9 Maths chapter 2 Exercise 2.2 then feel free to ask in the comments section down below.

To watch Free Learning Videos on Class 9 by Kota’s top Faculties Install the eSaral App

Here we have listed Class 9 maths chapter 2 exercise 2.2 solutions in PDF that is prepared by Kota’s top IITian’s Faculties by keeping Simplicity in mind.

If you want to score high in your class 9 Maths Exam then it is very important for you to have a good knowledge of all the important topics, so to learn and practice those topics you can use eSaral NCERT Solutions.

In this article, we have listed NCERT Solutions for Class 9 Maths chapter 2 Exercise 2.2 that you can download to start your preparations anytime.

So, without wasting more time Let’s start.

**Download The PDF of NCERT Solutions for Class 9 Maths chapter 2 Exercise 2.2 "Polynomials"**

So, that’s all from this article. I hope you enjoyed this post. If you found this article helpful then please share it with other students.

#### All Questions of Chapter 2 Exercise 2.2

Once you complete the chapter 2 then you can revise Ex. 2.2 by solving following questions

Q1. Find the value of the polynomial $5 x-4 x^{2}+3$ at

(i) $\mathrm{x}=0$

(vi) $\mathrm{x}=-1$

(iii) $\mathrm{x}=2$

Q2. Find $\mathrm{p}(0), \mathrm{p}(1), \mathrm{p}(2)$, for each of the following polynomials :

(i) $p(y)=y^{2}-y+1$

(ii) $\mathrm{p}(\mathrm{t})=2+\mathrm{t}+2 \mathrm{t}^{2}-\mathrm{t}^{3}$

(iii) $\mathrm{p}(\mathrm{x})=\mathrm{x}^{3}$

(iv) $\mathrm{p}(\mathrm{x})=(\mathrm{x}-1)(\mathrm{x}+1)$

Q3. Verify whether the following are zeroes of the polynomial, indicated against them,

(i) $\mathrm{p}(\mathrm{x})=3 \mathrm{x}+1, \mathrm{x}=-\frac{1}{3}$

(ii) $\mathrm{p}(\mathrm{x})=5 \mathrm{x}-\pi, \mathrm{x}=\frac{4}{5}$

(iii) $\mathrm{p}(\mathrm{x})=\mathrm{x}^{2}-1, \mathrm{x}=1,-1$

(iv) $\mathrm{p}(\mathrm{x})=(\mathrm{x}+1)(\mathrm{x}-2), \mathrm{x}=-1,2$

(v) $\mathrm{p}(\mathrm{x})=\mathrm{x}^{2}, \mathrm{x}=0$

(vi) $\mathrm{p}(\mathrm{x})=\ell \mathrm{x}+\mathrm{m}, \mathrm{x}=-\frac{\mathrm{m}}{\ell}$

(vii) $\mathrm{p}(\mathrm{x})=3 \mathrm{x}^{2}-1, \mathrm{x}=-\frac{1}{\sqrt{3}}, \frac{2}{\sqrt{3}}$

(viii) $\mathrm{p}(\mathrm{x})=2 \mathrm{x}+1, \mathrm{x}=\frac{1}{2}$

Q4. Find the zero of the polynomial in each of the following cases:

(i) $p(x)=x+5$

(ii) $\mathrm{p}(\mathrm{x})=\mathrm{x}-5$

(iii) $\mathrm{p}(\mathrm{x})=2 \mathrm{x}+5$

(iv) $\mathrm{p}(\mathrm{x})=3 \mathrm{x}-2$

(v) $\mathrm{p}(\mathrm{x})=3 \mathrm{x}$

(vi) $\mathrm{p}(\mathrm{x})=\mathrm{ax}, \mathrm{a} \neq 0$

(vii) $\mathrm{p}(\mathrm{x})=\mathrm{cx}+\mathrm{d}, \mathrm{c} \neq 0, \mathrm{c}, \mathrm{d}$ are real numbers.

Also Read,

Download Class 9 NCERT Maths Book Free

Download Class 9 NCERT Maths Exemplar Free

Download Complete Solutions for Class 9 chapter 2 PDF

Class 9 Maths Chapter 1 Exercise 1.1 Solutions

Class 9 Maths Chapter 1 Exercise 1.2 Solutions

Class 9 Maths Chapter 1 Exercise 1.3 Solutions

If you have any Confusion related to NCERT Solutions for Class 9 Maths chapter 2 Exercise 2.2 then feel free to ask in the comments section down below.

To watch Free Learning Videos on Class 9 by Kota’s top Faculties Install the eSaral App