1 gram of a carbonate

Question:

1 gram of a carbonate $\left(\mathrm{M}_{2} \mathrm{CO}_{3}\right)$ on treatment with excess $\mathrm{HCl}$ produces $0.01186$ mole of $\mathrm{CO}_{2}$. the molar mass of $\mathrm{M}_{2} \mathrm{CO}_{3}$ in $\mathrm{g} \mathrm{mol}^{-1}$ is :-

  1. 1186

  2. 84.3

  3. 118.6

  4. 11.86


Correct Option: , 2

Solution:

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