# 1500 families with 2 children were selected randomly, and the following data were recorded:

Question:

1500 families with 2 children were selected randomly, and the following data were recorded:

If a family is chosen at random, compute the probability that it has:

1. No girl

2. 1 girl

3. 2 girls

4. At most one girl

5. More girls than boys

Solution:

1. Probability of having no girl in a family $=\frac{\text { No of families having no girl }}{\text { Total no of families }}$

$=\frac{211}{1500}=0.1406$

2. Probability of having 1 girl in a family $=\frac{\text { No of families having } 1 \text { girl }}{\text { Total no of families }}$

$=\frac{814}{1500}$

$=\frac{407}{750}=0.5426$

3. Probability of having 2 girls in a family $=\frac{\text { No of families having } 2 \text { girls }}{\text { Total no of families }}$

$=\frac{475}{1500}=0.3166$

4. Probability of having at the most one girl $=\frac{\text { No of families having at the most one girl }}{\text { Total no of families }}$

$=\frac{211+814}{1500}$

$=\frac{1025}{1500}=0.6833$

5. Probability of having more girls than boys $=\frac{\text { No of families having more girls than boys }}{\text { Total no of families }}$

$=\frac{475}{1500}=0.31$