Question:
A bag contains 3 white, 4 red and 5 black balls. One ball is drawn at random. What is the probability that the ball drawn is neither black nor white?
(a) $\frac{1}{4}$
(b) $\frac{1}{2}$
(C) $\frac{1}{3}$
(d) $\frac{3}{4}$
Solution:
(c) $\frac{1}{3}$
Explanation:
Total possible outcomes = Total number of balls
$=(3+4+5)=12$
Total number of balls that are non-black and non-white = 4
$\therefore P$ (getting a ball that is neither black nor white) $=\frac{4}{12}=\frac{1}{3}$
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