A charge ' q ' is placed at one corner of a cube as shown in figure.

Question:

A charge ' $q$ ' is placed at one corner of a cube as shown in figure. The flux of electrostatic field $E$ though the shaded area is:

  1. (1) $\frac{q}{48 \varepsilon_{0}}$

  2. (2) $\frac{q}{8 \varepsilon_{0}}$

  3. (3) $\frac{q}{24 \varepsilon_{0}}$

  4. (4) $\frac{q}{4 \varepsilon_{0}}$


Correct Option: , 3

Solution:

(3)

$\phi=\frac{q}{24 \varepsilon_{0}}$

$\phi_{T}=\left(\frac{q}{24 \varepsilon_{0}}+\frac{q}{24 \varepsilon_{0}}\right) \times \frac{1}{2}$

$\phi_{T}=\frac{q}{24 \varepsilon_{0}}$

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