A child has die whose 6 faces show the letters given below.
The die is thrown once. What is the probability of getting (i) A, (ii) B?
When the die is thrown once, then any one of the six faces can show up.
∴ Total number of outcomes = 6
(i) There are 3 faces on the die showing the letter A.
$\therefore \mathrm{P}($ Getting the letter $\mathrm{A})=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{3}{6}=\frac{1}{2}$
(ii) There are 2 faces on the die showing the letter B.
Favourable number of outcomes = 2
$\therefore \mathrm{P}($ Getting the letter $\mathrm{B})=\frac{\text { Favourable number of outcomes }}{\text { Total number of outcomes }}=\frac{2}{6}=\frac{1}{3}$
Favourable number of outcomes = 3
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