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# A coin is tossed 1000 times with the following sequence:

Question:

A coin is tossed 1000 times with the following sequence: Head: 455, Tail = 545. Compute the probability of each event

Solution:

It is given that the coin is tossed 1000 times. The number of trials is 1000

Let us denote the event of getting head and of getting tails be E and F respectively. Then

Number of trials in which the E happens = 455

So,

Probability of $\mathrm{E}=\frac{\text { Number of even theads }}{\text { Total no of trials }}$

i.e. $P(E)=\frac{455}{1000}=0.455$

Similarity, the probability of the event getting a tail $=\frac{\text { Number of tails }}{\text { Total no of trials }}$

i.e. $P(F)=\frac{545}{1000}=0.545$