A coin is tossed 1000 times with the following sequence: Head: 455, Tail = 545. Compute the probability of each event
It is given that the coin is tossed 1000 times. The number of trials is 1000
Let us denote the event of getting head and of getting tails be E and F respectively. Then
Number of trials in which the E happens = 455
So,
Probability of $\mathrm{E}=\frac{\text { Number of even theads }}{\text { Total no of trials }}$
i.e. $P(E)=\frac{455}{1000}=0.455$
Similarity, the probability of the event getting a tail $=\frac{\text { Number of tails }}{\text { Total no of trials }}$
i.e. $P(F)=\frac{545}{1000}=0.545$
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