**Question:**

**A cricket bowler releases the ball in two different ways**

**(a) giving it only horizontal velocity and**

**(b) giving it horizontal velocity and a small downward velocity.**

**The speed vs at the time of release is the same. Both are released at a height H from the ground. Which one will have greater speed when the ball hits the **

**ground? Neglect air resistance.**

**Solution:**

(a)

$\frac{1}{2} v_{z}^{2}=g H \Rightarrow v_{z}=\sqrt{2 g H}$

Speed at ground is given as:

$\sqrt{v_{s}^{2}+v_{z}^{2}}=\sqrt{v_{s}^{2}+2 g H}$

(b)

$\frac{1}{2} m v_{s}^{2}+m g H$ is the total energy of the ball when it hits the ground.

Therefore, (a) and (b) have the same speed.