A dealer sold a camera for Rs 1080 gaining

Question:

A dealer sold a camera for Rs 1080 gaining $\frac{1}{8}$ of its cost price. Find

(i) the cost price of the camera, and (ii) the gain per cent earned by the dealer.

Solution:

SP of the camera $=$ Rs. 1080

Let Rs $x$ be the CP.

Gain $=$ Rs. $\frac{1}{8} x \quad \ldots(\mathrm{i})$

Also, gain $=\mathrm{SP}-\mathrm{CP}$

$=$ Rs. $(1080-x) \quad \ldots$ (ii)

From (i) and (ii), we have :

$\frac{1}{8} x=1080-x$

$\Rightarrow x=8640-8 x$

$\Rightarrow 9 x=8640$

$\Rightarrow \mathrm{x}=960$

$\therefore \mathrm{CP}=$ Rs. 960

Now, gain $=\frac{1}{8} \mathrm{x}$

$=\frac{960}{8}$

$=$ Rs. 120

$\therefore$ Gain percentage $=\left(\frac{120}{960} \times 100\right) \%$

$=12 \frac{1}{2} \%$

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