Question:
A die is thrown once. The probability of getting a prime number is
(a) $\frac{2}{3}$
(b) $\frac{1}{3}$
(C) $\frac{1}{2}$
(d) $\frac{1}{6}$
Solution:
(C) $\frac{1}{2}$
Explanation:
In a single throw of a die, the possible outcomes are:
1, 2, 3, 4, 5, 6
Total number of possible outcomes = 6
Let E be the event of getting a prime number.
Then, the favourable outcomes are 2, 3 and 5.
Number of favourable outcomes = 3
$\therefore$ Probability of getting a prime number $=P(E)=\frac{\text { Number of favorable outcomes }}{\text { Total number of possible outcomes }}=\frac{3}{6}=\frac{1}{2}$
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