A die is thrown twice. What is the probability that

Total number of outcomes = 6 × 6

= 36

(i)Total number of outcomes when 5 comes up on either time are (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (1, 5), (2, 5), (3, 5), (4, 5), (6, 5)

Hence, total number of favourable cases = 11

$P(5$ will come up either time $)=\frac{11}{36}$

$P(5$ will not come up either time $)=1-\frac{11}{36}=\frac{25}{36}$

(ii) Total number of cases, when 5 can come at least once $=11$

$P(5$ will come at least once $)=\frac{11}{36}$