Question:
A first order reaction takes 40 min for 30% decomposition. Calculate t1/2.
Solution:
For a first order reaction,
$t=\frac{2.303}{k} \log \frac{[\mathrm{R}]_{0}}{[\mathrm{R}]}$
$k=\frac{2.303}{40 \mathrm{~min}} \log \frac{100}{100-30}$
$=\frac{2.303}{40 \mathrm{~min}} \log \frac{10}{7}$
$=8.918 \times 10^{-3} \mathrm{~min}^{-1}$
Therefore, t1/2 of the decomposition reaction is
$t_{1 / 2}=\frac{0.693}{k}$
$=\frac{0.693}{8.918 \times 10^{-3}} \mathrm{~min}$
= 77.7 min (approximately)