A hollow garden roller, 63 cm wide with a girth of 440 cm, is made of 4 cm thick iron.

Here, R = Outer radius

r = Inner radius

t = Thickness = 4 cm

w = Width = 63 cm

Girth = 440 cm = 2πR

$\mathrm{R}=\frac{440}{2 \times \frac{22}{7}}=70 \mathrm{~cm}$

r = R − t = 70 cm − 4 cm = 66 cm

Volume of the iron $=\pi\left(R^{2}-r^{2}\right) w=\frac{22}{7}-\left(70^{2}-66^{2}\right)-(63)=107712 \mathrm{~cm}^{3}$

Hence, volume of the iron is 107712 cm3.