A horse is placed for grazing inside a rectangular field 40 m by 36 m and is tethered to one corner by a rope 14 m long. Over how much area can it graze? (Take π = 22/7)
It is given that a horse is tethered to one corner of a rectangular field (40 m × 36 m) by a 14 m long rope.
Let r m be the radius of a circle. Then area A of circle is
$A=\pi \mathrm{r}^{2} \mathrm{~m}^{2}$
$=\frac{22}{7} \times 14 \times 14 \mathrm{~m}^{2}$
$=616 \mathrm{~m}^{2}$
Since the horse can graze inside the rectangular field only, the required area is quadrant of circle. So,
Required area $=\frac{\mathrm{A}}{4}=\frac{616}{4}=154 \mathrm{~m}^{2}$
Hence the horse can graze 154 m2 area.
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