A line cutting off intercept – 3 from the y-axis

Solution:

A. 5y – 3x + 15 = 0

Explanation:

Given that $\tan \theta=\frac{3}{5}$

We know that,

Slope of a line, $m=\tan \theta$

$\Rightarrow$ Slope of line, $\mathrm{m}=\frac{3}{5}$

Since, the lines cut off intercepts $-3$ on $y$-axis then the line is passing through the point $(0,-3)$.

the point $(0,-3)$.

 

So, the equation of line is

$y-y_{1}=m\left(x-x_{1}\right)$

$\Rightarrow y-(-3)=\frac{3}{5}(x-0)$

$\Rightarrow y+3=\frac{3}{5} x$

$\Rightarrow 5 y+15=3 x$

$\Rightarrow 5 y-3 x+15=0$

Hence, the correct option is (a)