A right triangle $A B C$ with sides $5 \mathrm{~cm}$,

Solution:



When right-angled $\triangle \mathrm{ABC}$ is revolved about its side $12 \mathrm{~cm}$, a cone with height $(h)$ as $12 \mathrm{~cm}$, radius $(r)$ as $5 \mathrm{~cm}$, and slant height $(l) 13 \mathrm{~cm}$ will be formed.

Volume of cone $=\frac{1}{3} \pi r^{2} h$

$=\left[\frac{1}{3} \times \pi \times(5)^{2} \times 12\right] \mathrm{cm}^{3}$

$=100 \pi \mathrm{cm}^{3}$

Therefore, the volume of the cone so formed is $100 \pi \mathrm{cm}^{3}$.