# A soft drink is available in two packs:

Question:

A soft drink is available in two packs:

(i) a tin can with a rectangular base of length 5 cm, breadth 4 cm and height 15 cm, and

(ii) a plastic cylinder with circular base of diameter 7 cm and height 10 cm. Which container has greater capacity and by how much?

Solution:

(i) Length of tin can, l = 5 cm

Breadth of tin can, b = 4 cm

Height of tin can, h = 15 cm

∴ Volume of soft drink in tin can = l × b × h = 5 × 4 × 15 = 300 cm3

(ii) Radius of plastic cylinder, $r=\frac{7}{2} \mathrm{~cm}$

Height of plastic cylinder, h = 10 cm

$\therefore$ Volume of soft drink in plastic cylinder $=\pi r^{2} h=\frac{22}{7} \times\left(\frac{7}{2}\right)^{2} \times 10=385 \mathrm{~cm}^{3}$

So, the capacity of the plastic cylinder pack is greater than the capacity of the tin can pack.

Difference in the capacities of the two packs = 385 − 300 = 85 cm3

Thus, the capacity of the plastic cylinder pack is 85 cm3 more than the capacity of the tin can pack.