A vessel in the form of a hemispherical bowl is full of water.

Given that

Volume of water in the hemispherical bowl = Volume of water in the cylinder

Let h be the height to which water rises in the cylinder

Inner radii of the bowl = r1 = 3.5 cm

Inner radii of the bowl = r2 = 7 cm

$\frac{2}{3} \pi r_{1}^{3}=\pi r_{2}^{2} h$

$\mathrm{h}=\frac{2 \mathrm{r}_{1}^{3}}{3 \mathrm{r}_{2}^{2}}$

$h=\frac{2(3.5)^{3}}{3\left(7^{2}\right)}$

h = 7/12 cm