An athlete takes 2.0s to reach his maximum speed of 18.0 km/h.

Question:

An athlete takes 2.0s to reach his maximum speed of 18.0 km/h. What is the magnitude of his average acceleration?

Solution:

$u=0 ; v=18 \times \frac{5}{18}=5 \mathrm{~m} / \mathrm{s} ; \mathrm{t}=2 \mathrm{sec}$

$\mathrm{v}=\mathrm{u}+\mathrm{at}$

$5=0+a(2)$

$\mathrm{a}=2.5 \mathrm{~m} / \mathrm{s}^{2}$

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