An element has a face-centred cubic (fcc) structure

Question:

An element has a face-centred cubic (fcc) structure with a cell edge of a. The distance between the centres of two nearest tetrahedral voids in the lattice is :

  1. $\frac{a}{2}$

  2. $a$

  3. $\frac{3}{2} a$

  4. $\sqrt{2} a$


Correct Option: 1

Solution:

Distance between two nearest tetrahedral void

$=\left(\frac{a}{2}\right)$

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