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# At very high frequencies, the effective impendance

Question:

At very high frequencies, the effective impendance

of the given circuit will be $\Omega .$

Solution:

$\mathrm{X}_{\mathrm{L}}=2 \pi \mathrm{fL}$

$\mathrm{f}$ is very large

$\therefore \mathrm{X}_{\mathrm{L}}$ is very large hence open circuit.

$X_{C}=\frac{1}{2 \pi f C}$

$\mathrm{f}$ is very large.

$\therefore \mathrm{X}_{\mathrm{C}}$ is very small, hence short circuit.

Final circuit

$Z_{\mathrm{cq}}=1+\frac{2 \times 2}{2+2}=2$