Question:
Calculate the maximum kinetic energy of the beta particle emitted in the following decay scheme:
$12 \mathrm{~N} \rightarrow{ }^{12} \mathrm{C}^{*}+\mathrm{e}^{+}+\mathrm{V}$
${ }^{12} \mathrm{C}^{*} \rightarrow{ }^{12} \mathrm{C}+\gamma(4.43 \mathrm{MeV})$
The atomic mass of ${ }^{12} \mathrm{~N}$ is $12.018613 \mathrm{u}$
Solution:
