Question:
Concentric metallic hollow spheres of radii $\mathrm{R}$ and $4 \mathrm{R}$ hold charges $\mathrm{Q}_{1}$ and $\mathrm{Q}_{2}$ respectively. Given that surface charge densities of the concentric spheres are equal, the potential difference $V(R)-V(4 R)$ is:
Correct Option: 1,
Solution:
$\mathrm{E}=\frac{\mathrm{KQ}_{1}}{\mathrm{r}^{2}}$
$\Delta V=\int_{R}^{4 R} E d r=\frac{3 K Q_{1}}{4 R}$
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