D and E are points on sides AB and AC respectively of ΔABC such that

Question. D and E are points on sides AB and AC respectively of ΔABC such that ar (DBC) = ar (EBC). Prove that DE || BC.


Solution:



Since ΔBCE and ΔBCD are lying on a common base BC and also have equal areas, ΔBCE and ΔBCD will lie between the same parallel lines.

$\therefore \mathrm{DE} \| \mathrm{BC}$

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