Each side of an equilateral triangle is 10 cm.
Each side of an equilateral triangle is 10 cm.
Find
(i) the area of the triangle and
(ii) the height of the triangle.
(i) The area of the equilateral triangle $=\frac{\sqrt{3}}{4} \times \operatorname{side}^{2}$
$=\frac{\sqrt{3}}{4} \times 10^{2}$
$=\frac{\sqrt{3}}{4} \times 100$
$=25 \sqrt{3} \mathrm{~cm}^{2}$
or $25 \times 1.732=43.3 \mathrm{~cm}^{2}$
So, the area of the triangle is $25 \sqrt{3} \mathrm{~cm}^{2}$ or $43.3 \mathrm{~cm}^{2}$.
(ii) As, area of the equilateral triangle $=25 \sqrt{3} \mathrm{~cm}^{2}$
$\Rightarrow \frac{1}{2} \times$ Base $\times$ Height $=25 \sqrt{3}$
$\Rightarrow \frac{1}{2} \times 10 \times$ Height $=25 \sqrt{3}$
$\Rightarrow 5 \times$ Height $=25 \sqrt{3}$
$\Rightarrow$ Height $=\frac{25 \sqrt{3}}{5}=5 \sqrt{3}$
or height $=5 \times 1.732=8.66 \mathrm{~m}$
$\therefore$ The height of the triangle is $5 \sqrt{3} \mathrm{~cm}$ or $8.66 \mathrm{~cm}$.