Each side of an equilateral triangle measures 8 cm.

Question:

Each side of an equilateral triangle measures $8 \mathrm{~cm}$. Find

(i) the area of the triangle, correct to 2 places of decimal and

(ii) the height of the triangle, correct to 2 places of decimal. Take $\sqrt{3}=1.732$.

Solution:

Side of the equilateral triangle = 8 cm

(i)

Area of equilateral triangle $=\frac{\sqrt{3}}{4} \times(\text { Side })^{2}$

$=\frac{\sqrt{3}}{4} \times(8)^{2}$

$=\frac{1.732 \times 64}{4}$

$=27.71 \mathrm{~cm}^{2}$

(ii)

Height $=\frac{\sqrt{3}}{2} \times$ Side

$=\frac{\sqrt{3}}{2} \times 8$

$=\frac{1.732 \times 8}{2}$

$=6.93 \mathrm{~cm}$

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