Question:
Evaluate: 3√27 + 3√0.008 + 3√0.064
Solution:
We have, $\sqrt[3]{27}+\sqrt[3]{0.008}+\sqrt[3]{0.064}$
$=(27)^{1 / 3}+(0.008)^{1 / 3}+(0.064)^{1 / 3}$
$=(3 \times 3 \times 3)^{\frac{1}{3}}+(0.2 \times 0.2 \times 0.2)^{\frac{1}{3}}+(0.4 \times 0.4 \times 0.4)^{\frac{1}{3}}$
$=(3)^{3 \times \frac{1}{3}}+(0.2)^{3 \times \frac{1}{3}}+(0.4)^{3 \times \frac{1}{3}}$
$=3+0.2+0.4=3.6$
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