Evaluate:

$\sqrt[3]{1728}$

By prime factorisation:

$1728=2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3$

$=(2 \times 2 \times 2) \times(2 \times 2 \times 2) \times(3 \times 3 \times 3)=2^{3} \times 2^{3} \times 3^{3}$

$\therefore \sqrt[3]{1728}=(2 \times 2 \times 3)=12$