Question:
Evaluate: $\int \sec x(\sec x+\tan x) d x$
Solution:
Given, $\int \sec x(\sec x+\tan x) d x$
We know that, $\int \frac{1}{x^{2}+a^{2}} d x=\frac{1}{a} \tan ^{-1} \frac{x}{a}$
By comparison, $a=4$
$=\frac{1}{4} \tan ^{-1} \frac{x}{4}+c$
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