Factorise:
Question:

Factorise:
x2 + 6ax + 9a2

Solution:

We have:

$x^{2}+6 a x+9 a^{2}=x^{2}+2 \times x \times 3 a+(3 a)^{2}$

$=(x+3 a)^{2}$

$\therefore x^{2}+6 a x+9 a^{2}=(x+3 a)^{2}$

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