Question:
Factorise
$x^{4} y^{4}-x y$
Solution:
Using the identity
$a^{3}-b^{3}=(a-b)\left(a^{2}+b^{2}+a b\right)$
$x^{4} y^{4}-x y=x y\left(x^{3} y^{3}-1\right)$
$=x y(x y-1)\left(x^{2} y^{2}+1+x y\right)$
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