Question:
Factorize:
$216 x^{3}+\frac{1}{125}$
Solution:
$216 x^{3}+\frac{1}{125}=(6 x)^{3}+\left(\frac{1}{5}\right)^{3}$
$=\left(6 x+\frac{1}{5}\right)\left[(6 x)^{2}-6 x \times \frac{1}{5}+\left(\frac{1}{5}\right)^{2}\right]$
$=\left(6 x+\frac{1}{5}\right)\left(36 x^{2}-\frac{6 x}{5}+\frac{1}{25}\right)$
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