Question:
Factorize:
$8 a^{3}-b^{3}-4 a x+2 b x$
Solution:
$8 a^{3}-b^{3}-4 a x+2 b x=\left[(2 a)^{3}-(b)^{3}\right]-2 x(2 a-b)$
$=(2 a-b)\left[(2 a)^{2}+2 a b+b^{2}\right]-2 x(2 a-b)$
$=(2 a-b)\left(4 a^{2}+2 a b+b^{2}\right)-2 x(2 a-b)$
$=(2 a-b)\left(4 a^{2}+2 a b+b^{2}-2 x\right)$
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