Fill in the blanks:

Question:

Fill in the blanks:

(i) $\frac{-4}{13}-\frac{-3}{26}=. .$

(ii) $\frac{-9}{14}+\ldots=-1$

(iii) $\frac{-7}{9}+\ldots=3$

(iv) $\ldots+\frac{15}{23}=4$

Solution:

(i) $\frac{-4}{13}-\frac{-3}{26}=\frac{-8}{26}-\frac{-3}{26}=\frac{-8-(-3)}{26}=\frac{-8+3}{26}=\frac{-5}{26}$

(ii) $\frac{-9}{14}+x=-1$

$\Rightarrow x=-1-\frac{-9}{14}$

$\Rightarrow x=\frac{-14}{14}-\frac{-9}{14}$

$\Rightarrow x=\frac{-14-(-9)}{14}$

$\Rightarrow x=\frac{-14+9}{14}$

$\Rightarrow x=\frac{-5}{14}$

(iii) $\frac{-7}{9}+x=3$

$\Rightarrow x=3-\frac{-7}{9}$

$\Rightarrow x=\frac{27}{9}-\frac{-7}{9}$

$\Rightarrow x=\frac{27-(-7)}{9}$

$\Rightarrow x=\frac{27+7}{9}$

$\Rightarrow x=\frac{34}{9}$

$($ iv $) x+\frac{15}{23}=4$

$\Rightarrow x=4-\frac{15}{23}$

$\Rightarrow x=\frac{92}{23}-\frac{15}{23}$

$\Rightarrow x=\frac{92-15}{23}$

$\Rightarrow x=\frac{77}{23}$

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now