Question:
Find the dimensions of Planck's constant $h$ from the equation $E=h v$ where $E$ is energy and $v$ is frequency
Solution:
$h=\frac{E}{V}$
So, $[\mathrm{h}]=\left[\mathrm{ML}^{2} \mathrm{~T}^{-2}\right] /\left[\mathrm{T}^{-1}\right]=\left[\mathrm{ML}^{2} \mathrm{~T}^{-1}\right]$
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.