Find the surface area of a cube whose edge is
(i) 1.2 m
(ii) 27 cm
(iii) 3 cm
(iv) 6 m
(v) 2.1 m
(i) Edge of the a cube $=1.2 \mathrm{~m}$
$\therefore$ Surface area of the cube $=6 \times(\text { side })^{2}=6 \times(1.2)^{2}=6 \times 1.44=8.64 \mathrm{~m}^{2}$.
(ii) Edge of the a cube $=27 \mathrm{~cm}$
$\therefore$ Surface area of the cube $=6 \times(\text { side })^{2}=6 \times(27)^{2}=6 \times 729=4374 \mathrm{~cm}^{2}$
(iii) Edge of the a cube $=3 \mathrm{~cm}$
$\therefore$ Surface area of the cube $=6 \times(\text { side })^{2}=6 \times(3)^{2}=6 \times 9=54 \mathrm{~cm}^{2}$
(iv) Edge of the a cube $=6 \mathrm{~m}$
$\therefore$ Surface area of the cube $=6 \times(\text { side })^{2}=6 \times(6)^{2}=6 \times 36=216 \mathrm{~m}^{2}$
(v) Edge of the a cube $=2.1 \mathrm{~m}$
$\therefore$ Surface area of the cube $=6 \times(\text { side })^{2}=6 \times(2.1)^{2}=6 \times 4.41=26.46 \mathrm{~m}^{2}$
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