Find the value

Question:

Find the value

$64 a^{3}+125 b^{3}+240 a^{2} b+300 a b^{2}$

Solution:

$=(4 a)^{3}+(5 b)^{3}+3(4 a)^{2}(5 b)+3(4 a)(5 b)^{2}$

$\left[\therefore a^{3}+b^{3}+3 a^{2} b+3 a b^{2}=(a+b)^{3}\right]$

$=(4 a+5 b)^{3}$

$=(4 a+5 b)(4 a+5 b)(4 a+5 b)$

$\therefore 64 a^{3}+125 b^{3}+240 a^{2} b+300 a b^{2}$

$=(4 a+5 b)(4 a+5 b)(4 a+5 b)$

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