Find the value

Question:

Find the value of $\tan ^{-1}\left(\tan \frac{9 \pi}{8}\right)$

Solution:

$\tan ^{-1}\left(\tan \frac{9 \pi}{8}\right)=\tan ^{-1}\left[\tan \left(\pi+\frac{\pi}{8}\right)\right]$

$=\tan ^{-1}\left[\tan \left(\frac{\pi}{8}\right)\right]$

$=\frac{\pi}{8}$

Leave a comment

Close
faculty

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now