find the value of

Given: $f(x)=x^{2}$

Firstly, we find the f(1.1)

Putting the value of x = 1.1 in the given eq., we get

$f(1.1)=(1.1)^{2}$

$\Rightarrow f(1.1)=1.21$

Similarly,

$f(1)=(1)^{2}$

$\Rightarrow f(1)=1$

Putting the value of f(1.1) and f(1) in eq. (i), we get

$\frac{\mathrm{f}(1.1)-\mathrm{f}(1)}{(1.1-1)}=\frac{1.21-1}{1.1-1}=\frac{0.21}{0.1}=2.1$

Hence, the value of $\frac{\mathrm{f}(1.1)-\mathrm{f}(1)}{(1.1-1)}=2.1$