Question:
Find the value of x in each of the following :
$2 \sin 3 x=\sqrt{3}$
Solution:
We have,
$2 \sin 3 x=\sqrt{3}$
$\Rightarrow \sin 3 x=\frac{\sqrt{3}}{2}$
Since, $\sin 60^{\circ}=\frac{\sqrt{3}}{2}$
Therefore,
$\sin 3 x=\frac{\sqrt{3}}{2}$
$\Rightarrow 3 x=60^{\circ}$
$\Rightarrow x=\frac{60^{\circ}}{3}$
$\Rightarrow x=20^{\circ}$
Therefore,
$x=20^{\circ}$
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