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First, a set of n equal resistors of R each are connected

Question:

First, a set of n equal resistors of R each are connected in series to a battery of emf E and internal resistance R. A current I is observed to flow. Then the n resistors are connected in parallel to the same battery. It is observed that the current is increased 10 times. What is ‘n’?

Solution:

When the resistors are in series combination, the current is given as I = E/R+nR

When the resistors are in parallel combination, current is given as 10I = E/(R+R/n)

Solving the two equations, we get

n = 10

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