Question: For a first order reaction, (A) $\rightarrow$ products, the concentration of A changes from $0.1 \mathrm{M}$ to $0.025 \mathrm{M}$ in 40 minutes. The rate of reaction when the concentration of $\mathrm{A}$ is $0.01 \mathrm{M}$ is :
$1.73 \times 10^{-4} \mathrm{M} / \mathrm{min}$
$1.73 \times 10^{-5} \mathrm{M} / \mathrm{min}$
$3.47 \times 10^{-4} \mathrm{M} / \mathrm{min}$
$3.47 \times 10^{-5} \mathrm{M} / \mathrm{m}$
Correct Option: , 3
Solution:
