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For the same objective,

Question:

For the same objective, find the ratio of the least separation between two points to be distinguished by a microscope for light of 5000 Ao and electrons accelerated through 100V used as the illuminating substance.

Solution:

5000 Ao = 5000 × 10-10 m

1/d = 2 sin β/1.22λ

dmin = 1.22 λ/ 2 sin β

λd = 1.22/10 × 10-10 m

When the 100V light is used, d’min = 1.22 λd/ 2 sin β

d’min = 1.22 × 1.22 × 10-10/2 sin β

The required ratio = dmin/d’min = 1.22/5000 = 0.244 × 10-3

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